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This is the most accurate equation I can think of to estimate a roller coaster's capacity per hour. Enjoy!

Let...

P = Persons Per Hour

C = Train Capacity

D = Ride Duration (Include loading time) (Change the time to a decimal [ex. 2:30 = 2.5 ; 2 1/2 minutes = 2.5 minutes - see below for more minutes to decimal conversions])

T = Number of Trains

Equation:

P = (C / D • 60)(T)

So, if I had a roller coaster that seated 36 people per train in 3 different trains and had a duration of 2:30 and an average loading time of 1:00, I would figure it out like so:

P = (36 / 3.5 • 60)(3)

I end up with about 1851 persons per hour.

Time to Decimal Conversion for Duration

Divide the number of seconds by 60. Round to the nearest hundredth (0.00)

Let...

P = Persons Per Hour

C = Train Capacity

D = Ride Duration (Include loading time) (Change the time to a decimal [ex. 2:30 = 2.5 ; 2 1/2 minutes = 2.5 minutes - see below for more minutes to decimal conversions])

T = Number of Trains

Equation:

P = (C / D • 60)(T)

So, if I had a roller coaster that seated 36 people per train in 3 different trains and had a duration of 2:30 and an average loading time of 1:00, I would figure it out like so:

P = (36 / 3.5 • 60)(3)

I end up with about 1851 persons per hour.

Time to Decimal Conversion for Duration

Divide the number of seconds by 60. Round to the nearest hundredth (0.00)

Yours multiplies by 60 to compensate for the number of minute sin an hour, mine multiplies by 3600 for the number of seconds in an hour. Thye will both yield the same results.

I'll use your example:

(36 C * 3 T * 60 [mins/hour]) / 3.5 D[mins]

the minutes cancel out

1851 rph

(36 C * 3 T * 3600 [sec/hour]) / 210 D[sec]

seconds cancel

1851 rph

Golfie wrote:This is the most accurate equation I can think of to estimate a roller coaster's capacity per hour. Enjoy!

Sorry, but I cannot enjoy that one...

Golfie wrote:Let...

P = Persons Per Hour

C = Train Capacity

D = Ride Duration (Include loading time) (Change the time to a decimal [ex. 2:30 = 2.5 ; 2 1/2 minutes = 2.5 minutes - see below for more minutes to decimal conversions])

T = Number of Trains

Equation:

P = (C / D • 60)(T)

So, if I had a roller coaster that seated 36 people per train in 3 different trains and had a duration of 2:30 and an average loading time of 1:00, I would figure it out like so:

P = (36 / 3.5 • 60)(3)

I end up with about 1851 persons per hour.

So, if I had a roller coaster that seated 36 people per train in 3 different trains and had a duration of 2:30 and an average loading time of 1:00,...

...and my trains would dispatch every 7 minutes (which equals 420 seconds), I would get a capacity of approx. 308 peeps per hour! (threehundred and eight!). Still there are three trains, 36 persons per train, and 1:00 loading time, and 2:30 ride time.

BTW: with german funfair dispatch (~ 28 seconds) the capacity with your example would be 4628(!) pph. Have three trains within the station (and a dozen more running...) and the loading time of 1:00 can easily be handled too.

So how's that? I'd humbly recomend you to start over...

Limits? NoLimits! http://nldc.interfix.net/u35

So duration includes ride time, loading time, and dispatch time? Because when I say loading time, I mean the time it takes for a full train to load and leave the station.

Could you clarify a little more?

Like he said, red, it's an estimation. It's saying the ride COULD get x number of people, not the ride IS getting.

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